Jump to content

Recommended Posts

Members dont see this ad
Posted

mmmmm i get about 3.4deg

 

tan^-1 (3*25.4/1300) = 3.34deg

 

either way, i think its a bit much for truck tyres? not htat i know anything about truck tyres, but they don't look like the type of tyre that would respond well to negative camber, especailly in straight line breaking.

 

 

 

 

yep ok wait what huh maths lesson plz :S

Posted

yep ok wait what huh maths lesson plz :S

I'm currently getting a maths lesson off a 15 year old on how to use pi. and too think i got high marks in my S/C for maths oh wait that was 6 years ago.

Posted (edited)

260 (D) x 3.14 = 816 div 360 = 2.26 so there fore 2.26 = 1 degree? so 1 degree for 1 inch drop. its currently 2 inches P/C so i could go crazy and drop 5 inches and still be on a safe limit of camber. although when braking and the nose dives a bit that is obviously going to increase mmmm oh and if i ever carry a decent weight in it which is unlikely

Edited by cinky

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
×
×
  • Create New...