November 11, 201114 yr comment_565577 So I bought some amber LED strips slapped them to a piece of anodized aluminum and was going to mount them on my grille. Just to make sure I hooked them up and they don't work. They work with only the turn signals but I can't get them to work with the turn signals and the park lamps on. I saw some other forums about putting diodes and resitors in but I am kinda lost on this one. Any help out there? I will post vid and pics when I'm done! Report
November 11, 201114 yr comment_565607 The LED's don't have enough resistance to make the flashers work, you can buy load resistors that you put in the circut. http://www.ebay.com.au/itm/12V-50W-LOAD-RESISTOR-AUTO-GLOBES-LED-LIGHT-PAIR-/220791852889?pt=AU_Car_Parts_Accessories&hash=item3368384f59 Report
November 11, 201114 yr comment_565646 I don't get it, are you trying to use the replace the indicators with the LEDs strips? If so, Reed is right. You can also buy flasher cans to suit LED indicators, they are pretty common on motorbikes and should solve the problem, and will save you the hassle of trying to figure out what resistor to use. Edited November 11, 201114 yr by rianwest Report
November 13, 201114 yr Author comment_565897 So with the new flasher can, I can just bypass the existing flasher or use in series? Report
November 13, 201114 yr comment_565904 http://www.customautoelectrics.com.au/page_50.html Are you replacing your indicators with LEDs? Or just adding in and extra pair of indicators which are LED? I don't understand electrics too well, but couldn't you run the LEDs in parallel to the standard indicators, and have 2 flashers: one for the standard indicators and one for the LEDs? That is if you are just adding an extra LED pair of indicators and not just replacing the standard indicaotrs with LEDS. Report
December 3, 201114 yr comment_569537 you will need to add a resistor in series with the LEDs to bring the resistance up to the same as the globe you replaced. remember: V=IR (ohm's law) P=VI (can't remember who's law :hmm: ) indicator is 21W at 12V P=VI 21=12I I=1.75 Amps resistance must be V=IR 12=1.75R R=6.857 Ohms so the resistance of the LEDs and resistor combined, because you will run them in series, must equal close to this if anyone sees a mistake feel free to correct me, and i know it could have been done in one step but it helps to step it out :P hope this helps Matt Report
December 6, 201114 yr Author comment_569981 totally...thanks! ill attatch pix if i ever finish this one Report
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